4.9t^2+27.6t-12=0

Solution for 4.9t^2+27.6t-12=0 equation:

4.9t^2+27.6t-12=0

a = 4.9; b = 27.6; c = -12;
Δ = b2-4ac
Δ = 27.62-4·4.9·(-12)
Δ = 996.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27.6)-\sqrt{996.96}}{2*4.9}=\frac{-27.6-\sqrt{996.96}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27.6)+\sqrt{996.96}}{2*4.9}=\frac{-27.6+\sqrt{996.96}}{9.8}
$